Question

Given:

Element Electronic Configuration

P

Q

R

S

1s2

2s2

1s2

2s2

2p6

3s2

3p1

1s2

2s2

2p6

3s1

1s2

2s2

2p4

(i) Arrange P, Q, R and S in decreasing order of their atomic radii.

(ii) Which one among these is a chalcogen?

(iii) Give the formula of the oxide formed by R and S.​

Answer 1

Answer:

this is a very hard question

Answer 2

Answer:

1. decreasing order of their atomic radii is R<Q<P<S
2. Q is a chalcogen
3. oxides of R is Na2O3 and oxides of S is O2

Explanation:

this is the correct answer