Math, asked by h4941658, 1 year ago

Given f(x)=(1+1/x)^x ,find f'(x) ?

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Answered by thyphamxuan

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(u^x)' = u^x.lnu.u'

f'(x)= (x+ 1/x)^x .ln(x+1/x) .(1-1/x^2)

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