given f(x) = 5x+2, g(x) =2x-3, h(x) =3x+1 , verify fo(goh) =(fog) oh
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EXPLANATION.
GIVEN.
=> f(x) = 5x + 2
=> g(x) = 2x - 3
=> h(x) = 3x + 1
verify that = fo(goh) = (fog)oh.
=> L.H.S. = fo(goh).
=> goh = g ( h(x))
=> g ( 3x + 1 )
=> 2 ( 3x + 1 ) - 3
=> 6x + 2 - 3
=> 6x - 1 = goh
=> fo(goh) = f(goh(x)).
=> f ( 6x - 1 )
=> 5 ( 6x - 1 ) + 2
=> 30x - 5 + 2
=> 30x - 3 = fo(goh).
R.H.S = (fog)oh.
=> fog = f (g(x))
=> f ( 2x - 3 )
=> 5 ( 2x - 3 ) + 2
=> 10x - 15 + 2
=> 10x - 13 = fog
=> (fog)oh = fog(h(x))
=> fog ( 3x + 1 )
=> 10 ( 3x + 1 ) - 13
=> 30x + 10 - 13
=> 30x - 3 = (fog)oh.
Therefore,
=> fo(goh) = (fog)oh.
HENCE VERIFIED.
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