Question

Given f(x)=squarerootof(x−3), what is f(4)?

Answer 1

Answer :

Given that,

f (x) = $\sqrt{(x-3)}$

Now, f (4)

= $\sqrt{(4-3)}$

= $\sqrt{1}$

= 1

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Answer 2

$\textbf{HELLO FRIEND HERE IS YOUR ANSWER,,,,,}$

$f(x) = \sqrt{(x - 3)} f(4)$

For,,,,

$f(4) = \sqrt{x - 3}$

Substituting with "x" with the given value "4".

$f(4) = \sqrt{4 - 3}$

Subtracting the numbers given under root squares;

$= > \sqrt{4 - 3} \\ \\ = \sqrt{1}$

Applying the rule of square roots;

$= > \sqrt{1} = 1$

Therefore,,,,,

$f(4) = > 1$

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HOPE THIS HELPS AND CLEARS YOUR DOUBTS RELATING FUNCTIONS!!!!