Given figure shows two long parallel wires P and Q separated by a distance of 4 cm and carrying equal currents of 100 A along opposite directions. Find the magnitude of the magnetic field.
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Answer:
We know B =µI/2πr where B is the magnitude of the magnetic field.
I is the current carried by the wires which are 100 A.
r is the distance between them.
We also know that µ = 4*3.14*10^-7 which is the constant.
Putting the values we get the magnitude
4*3.14*10^-7 X 100/2X 3.142 X 0.04
= 0.0005 T.
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