Question

Given:
(i) Cu²⁺ + 2e⁻ → Cu, Eo = 0.337 V
(ii) Cu²⁺ + e⁻ → Cu⁺, Eo = 0.153 V
Electrode potential, Eo for the reaction,
Cu⁺ + e⁻ → Cu, will be :
(a) 0.90 V (b) 0.30 V
(c) 0.38 V (d) 0.52 V

Answer 1

The electrode potential for the reaction is E∘=0.521 V

Option (D) is correct.

Explanation:

ΔG∘ = nFE∘  

For, Cu2+ + 2e− → Cu , ΔG∘1 = −2F ( 0.337 ) . . . . (1)

Cu2+ + e− → Cu+ , ΔG∘2 = −F(0.153) . . . (2)

Subtracting (2) from (1),

Cu+ + e− → Cu

ΔG∘ = −0.674 F + 0.153 F . . . (3)

nFE∘ = − 0.521 F

For equation (3):

n = 1

E∘ = 0.521 V

Thus the electrode potential for the reaction is E∘ = 0.521 V

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