Question

Given K = 2 ,L=8 ,M=11 ,N = 2 then find the number of electrons present in L =2

Answer 1

When L = 2, the maximum number of electrons present in it is 8.

Explanation:

• The given letter designation of shells is 'L'. From it the value of n is identified as 2, as values of n represents the position of the shell as given below:

1. n = 1 - K shell
2. n = 2 - L shell
3. n = 3 - M shell
4. n = 4 - N shell

• With the value of n, the maximum number of electrons that a shell can hold can be calculated using the formula $2n^2$.
• Accordingly, the maximum number of electrons in L-shell is:

n = 2

$2n^2 = 2\times(2)^2 = 2\times4 = 8$

• Thus it is inferred that when L = 2, it has 8 electrons.

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Answer 2

Answer:

The answer is below

Explanation: