Question

Given logx = 2m-n, logy=n-2m and logz=3m-2n find in terms of m and n the value of log x^2y^3/z^4

Answer 1

Given log x = 2m - n, log y = n - 2m, log z = 3m - 2n.

Given : log x^2y^3/z^4

We know that log(a/b) = log a - log b.

= > log x^2y^3 - log z^4

We know that log(ab) = log a + log b

= > logx^2 + log y^3 - log z^4

= > 2 log x + 3 log y - 4 log z

= > 2(2m - n) + 3(n - 2m) - 4(3m - 2n)

= > 4m - 2n + 3n - 6m - 12m + 8n

= > -14m + 9n.

Hope this helps!

Answer 2

Answer:

9n-14m

Step-by-step explanation:

hope it helps you mate!!