Question

Given: PQ = PR
m∠QPR = m∠SPK
m∠Q = m∠PRK Prove: PS = PK

Answer 1

Answer:

in ΔPQR we have ,

              PQ = PR

IN,       ∠PRR = ∠PQR

180° - ∠PQR = 180° - ∠PQR

          ∠PQR = ∠PSQ ...........1

IN ΔPSQ = PRK

         ∠SPQ = ∠RPK

             ∠Q = ∠R IS GIVEN IN QUESTION SO,

        ∠SPQ = ∠RPQ

so, by ASA congruence  we have ,

      ΔPSQ = ΔPRK

     So, PS = PK

hence prove..