X²-15X+54=0 solve quadratic equation using quadratic formula
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Answered by
1
Answer:
X2-15X+54 =0
compare with ax2+bx+c= 0
a=1 b= - 15 c=54
b2-4ac = (-15)२-4×1×54
b२-4ac =225-216
b२-4ac =9
hope it helps you
Answered by
0
Answer:
X² – 15x + 54 = 0
⇒ x² - 9x - 6x + 54 = 0
⇒ x (x - 9) - 6 (x - 9) = 0
⇒ (x - 6) (x - 9) = 0
⇒ (x - 6) = 0 or (x - 9) = 0
⇒ x = 6 or x = 9
So, 6 and 9 are the roots of the given quadratic equation.
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