given rectangle with a fixed perimeter of 24 metres if we increase the length by 1 metre bridge and the area will vary accordingly
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let breadth=x
length=y+1
perimeter=24 m
2(y+1+x)=24
2(x+y+1)=24
x+y+1=12
x+y=11
x=11-y
Area=l×b
=(y+1)×x
=(y+1)×(11-y)
=11y+11-y^2 -y
=11+10y-y^2 Ans.
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