Question

given: sin A =3/5
find 1)tan A
2)cos A


there is no diagram in my textbook
plz solve this

Answer 1

Step-by-step explanation:

this is the answer of your question

Answer 2

Answer:

$tanA = \dfrac{3}{4}$

$cosA = \dfrac{4}{5}$

Step-by-step explanation:

Given that-

$sinA = \dfrac{3}{5}$-

We know that- $sinA = \dfrac{Perpendicular}{Hypotenuse}$

So, Perpendicular = 3

Hypotenuse = 5

According to Pythagoras theorem-

$(Hypotenuse)^{2} = (Base)^{2}+ (Perpendicular)^{2}$

So, $(5)^{2} = (Base)^{2} + (3)^{2}$

$25 = Base^{2} + 9$

$25 - 9 = (Base)^{2}$

$(Base)^{2} = 16$

Base = 4

1. tanA = $\dfrac{Perpendicular}{Base}$

$tanA = \dfrac{3}{4}$

2. cosA = $\dfrac{Base}{Hypotenuse}$

$cosA = \dfrac{4}{5}$