Given :
sin alpha = 1/2 , prove that (3 cos alpha - 4 cos cube alpha) = 0
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SinA=1/2. (A= alpha)
SinA=sin30
A=30
3cosA-4cos3A
3cos30-4cos3'30
3×√3/2-4×(√3/2)3
3√3/2-12√3/8
3√3/2-3√3/2 =0.
SinA=sin30
A=30
3cosA-4cos3A
3cos30-4cos3'30
3×√3/2-4×(√3/2)3
3√3/2-12√3/8
3√3/2-3√3/2 =0.
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