Math, asked by ashadsheikh1666, 11 months ago

Given tanθ=1/√5, what is the value of cosec²θ-sec²θ/cosec²θ+sec²θ?

Answers

Answered by ItsUDIT
7

Step-by-step explanation:

tanθ = (1/√5)

tan² θ= 1/ 5 ---------(1)

As tan² θ = sec² θ - 1, we get:

sec² θ - 1 = 1/5

sec² θ = 1/5 + 1 = 6/5

Taking the reciprocal on both sides of equation (1), we get:

1/ tan² θ= 5

Cot ² θ = 5

As Cot² θ = Cosec² θ - 1, we get:

Cosec² θ - 1 = 5

Cosec² θ = 6

(cosec² θ - sec² θ) / (cosec² θ + sec² θ) = (6 - 6/5) / (6 + 6/5)

= (24/5) / (36/5)

= 24 / 36

= 2 / 3  .

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