given tan A = 4/3, find the other trigonometric ratio of the angel A
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Answered by
4
tan A =perpendicular/base
=} 4/3
so 4²+3²=hypothenuse²
25=hypotenuse ²
5=h
cotA=3/4
sinA=3/5 Or 4/5
cosA=4/5 Or 3/5
cosecA=5/3 Or 5/4
secA = 5/4 Or 5/3
all values are possible because base and perpendicular are not fixed....
Hope it helps u.....
=} 4/3
so 4²+3²=hypothenuse²
25=hypotenuse ²
5=h
cotA=3/4
sinA=3/5 Or 4/5
cosA=4/5 Or 3/5
cosecA=5/3 Or 5/4
secA = 5/4 Or 5/3
all values are possible because base and perpendicular are not fixed....
Hope it helps u.....
Answered by
2
by Pythagoras therom first of all we find out the hypotenuse
hypotenuse =5
cot A=3/4
sin A=4/5
cosec A=5/4
secA=3/5
cosA=5/3
hypotenuse =5
cot A=3/4
sin A=4/5
cosec A=5/4
secA=3/5
cosA=5/3
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