Question

given tan A + tan B + tan A tan B = 1 , then (A + B) is?
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Answer 1

Answer:

$tan \: a \: + \: tan \: b = 1 - tan \: a \: tan \: b$

$\frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } = 1$

$\tan(a + b) = 1 \: ans$

Answer 2

tana+tanb=1−tanatanb

=>{tan(a) + tan(b)} /{1 - tan(a) tan(b) } = 1

=> tan (a+b) = 1 => tan (a+b) = tan45 => (a+b) = tan^-1 tan45 => a+b = 45