Question

Given that 100.48 = x, 100.70 = y and xz = y2, then the value of z is close to:

Answer 1

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Answer 2

Answer:

The z value is close to 101.

Step-by-step explanation:

Given : $x=100.48$, $y=100.70$ and $xz=y^2$

To find : The value of z is close to?

Solution :

The equation is given by,

$xz=y^2$

Substitute, $x=100.48$ and $y=100.70$

$(100.48)z=(100.70)^2$

$(100.48)z=10140.49$

$z=\frac{10140.49}{(100.48)}$

$z=100.92$  

Therefore, The z value is close to 101.