Question

Given that 3a+4p=cp + 1, express in terms of a, b and c

Answer 1

Answer:

we know log (ab) = log a + log b; remember their bases must be same or else that identity isn’t valid

log 15 = log 3 +log 5;

C = [log k/(log3 + log5)];

1/C = (log3 + log5)/log k;

1/C = (log3/log k) + (log5/log k);

1/C = 1/A + 1/B;

1/C = (A + B)/AB;

or C = (AB)/ (A + B);

Step-by-step explanation: