Given that √5 is irrational prove that 3+2√5 is irrational
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- 2√5-3 = p/q
- 2√5 = p/q +3
- 2√5 = (p+3q)/q
- √5 = (p+3q)/2q
We can see that LHS is an irrational number which can never be equal to RHS which is a rational number. Therefore, our assumption that 2√5-3 is a rational number is wrong. 2√5-3 is not a rational number, it is an irrational number.
Hence proved.
Done!!
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Answer:
above one is correct...
Step-by-step explanation:
thanks
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