given that a(a+b) = 36 and b(a+b) = 64. where a and b are positive , find (a-b)
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add two equations
a^2+b^2+2ab=100
(a+b)^2=100
a+b=10
substitute in above equations
(a+b)^2-4ab=(a-b)^2
100-(4*3.6*6.4)=(a-b)^2
a-b=√7.14
a-b=2.8
a^2+b^2+2ab=100
(a+b)^2=100
a+b=10
substitute in above equations
(a+b)^2-4ab=(a-b)^2
100-(4*3.6*6.4)=(a-b)^2
a-b=√7.14
a-b=2.8
lol2lol:
its wrong
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