Question

Given that A + B = 90 degrees, show that root cosA cosecB-cosAsinB = sin A

Answer 1

Hey dearie

CosA cosec(90-A) - cosAsin(90-A)

CosA secA - cosAcosA

1 - cos^2A

Sin^2A

Hope itz helps uh

Answer 2

$\huge{\underline{\mathbb{\red{Answer}}}}$

CosA cosec(90-A)- cosAsin(90-A)

CosA SecA - CosACosA

$= > 1 - {cos}^{2} a$

$= > {sin}^{2} a$

______________________________________

$\huge{\underline{\mathbb{\pink{Thankyou}}}}$