given that a throw of three unbiased dice shows different faces the probability that one face shows 6is
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P(6)=1/3 or 0.33
(As it is given that there are different faces)
(As it is given that there are different faces)
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SOLUTION ;-
Probability that a 6 occurs on one die = 1/6
Probability that a 6 does not occur on one die = 1/1 - 1/6
= 5/6
Now, probability that a 6 occurs on at least one die = 1 - (Probability that a 6 occurs on none of the 3 dice)
= 1/1 - (5/6 × 5/6 × 5/6)
= 1/1 - 125/216
Taking LCM of the denominators and then solving it.
= 91/125
So, the probability is 91/125
Answer.
Probability that a 6 occurs on one die = 1/6
Probability that a 6 does not occur on one die = 1/1 - 1/6
= 5/6
Now, probability that a 6 occurs on at least one die = 1 - (Probability that a 6 occurs on none of the 3 dice)
= 1/1 - (5/6 × 5/6 × 5/6)
= 1/1 - 125/216
Taking LCM of the denominators and then solving it.
= 91/125
So, the probability is 91/125
Answer.
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