Given that AB and AC are tangents to the
circle and AC = BC, then <CAB in the given
figure is equal to
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Answer:
We know that the angle at circumference subtended by the diameter of the circle is right angle.
Thus ∠ACB=90
In △ABC
AC=BC (given)
=>∠CAB=∠CBA
Now,
∠CAB+∠CBA+∠ACB=180
=>∠CAB+∠CAB=180−90
=>∠CAB= 90/2
=>∠CAB=45
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