Question

Given that AB and AC are
tangents to the circle
and
Ac = BC, then /CAB
in the given figure
is equal to​

Answer 1

Answer:

k j jpvhocx9t gt rr7x7uf ysz d ucdu, 7fg 6ze ig r7 9g

Step-by-step explanation:

7xtxzd7 tx8vy9i f du gii gi f good friend gogo if i f hh oi f if

Answer 2

Answer:

We know that the angle at circumference subtended by the diameter of the circle is right angle.

Thus ∠ACB=90

In △ABC

 AC=BC (given)

=>∠CAB=∠CBA

Now,

 ∠CAB+∠CBA+∠ACB=180  

 

=>∠CAB+∠CAB=180−90

=>∠CAB=  90/2

=>∠CAB=45  

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Step-by-step explanation: