Given that an =( n²‐1/ n+3; n is even,nEN n²/2 n+1;n is odd ,nEN) then find a⁸ and a¹⁵
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Given that an =( n²‐1/ n+3; n is even,nEN n²/2
Correct option is
C
12
Given that:
Tn=n2+3
To find:
T3=?
Solution:
Tn=n2+3
T3=32+3
T3=9+3
T3=12
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