Given that D is the midpoint of AB and E is the midpoint of AC, find the value of X
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hey here is your answer
pls mark it as brainliest answer pls
so here we go
Step-by-step explanation:
now as e and d are midpoints of seg ac and ab respectively
we can apply midpoint theorem
so thus de is parallel to bc and de=half of bc
so here de=4x-6 and bc=7x+8
so accordingly
4x-6=1/2×7x+8
so 2(4x-6)=7x+8
ie 8x-12=7x+8
ie x=8+12
so x=20
this value of x is 20
u can verify the answer by substituting value of x in missing terms if de=1/2×bc ie lhs=rhs
our answer is ryt then
so (4×20)-6=1/2×(7×20)+8
ie 80-6=1/2×(140+8)
ie 74=1/2×148
thus 74=74
hence verified
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