Given that focal length, f= -10cm
Magnification, m= Image height/ Object height= 6/2 = 3
Also magnification= - v/u
3= -v/u
v= -3u
As 1/u + 1/v = 1/f
1/u + 1/-3u = 1/ -10
Therefore u= -6.667
So object should be placed at a distance of 6.667 cm in front of the mirror.
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