given that log 2= X log 3= y and log 7= z express the following expression in terms of X y and z
(1) log 12
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Given : log 2= X log 3= y and log 7= z
To Find : express log 12 in terms of X y and z
Solution:
log 12 = log ( 2 * 2 * 3)
=> log 12 = log ( 2² * 3)
log (ab) = log a + log b
=> log 12 = log ( 2²) + log 3
log aⁿ = n log a
=> log 12 = 2 log ( 2 ) + log 3
=> log 12 = 2x + y
log 12 = 2x + y + 0.z
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