Question

Given that log32 q – log2 r = 0, express r in term of q.
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Answer 1

Answer:

$r = {q}^{5}$

Step-by-step explanation:

$log_{32}(q) = log_{2}(r) \\ \\ \frac{1}{5} log_{2}(q) = log_{2}(r) \\ \\ {q}^{5} = r \\ \\ or \: \: \: \: \: \: \: \: r = {q}^{5}$