Given that logx = m+n and logy = m-n,
the value of log (10x^2
/y) is expressed in
terms of m and n as
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Answered by
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Answered 1 year ago
Thanks for A2A
Following formula are used :-
log (A/B) =log A - log B
log (C×D) =log C + log D
log (A^n) = n log A
If value of base is not mentioned then we assume it to be common logarithm so by default base become 10
So
Log 10 =1
Now
Log (10x / y^2)
= Log 10x - Log (y^2)
=Log 10 + Log x - 2 Log y
= 1 + m + n - 2 (m - n)
=1 + m + n - 2m + 2n
= 1 - m + 3n
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