Question

Given that logx = m+n and logy = m-n,

the value of log (10x^2

/y) is expressed in

terms of m and n as​

Answer 1

Answered 1 year ago

Thanks for A2A

Following formula are used :-

log (A/B) =log A - log B

log (C×D) =log C + log D

log (A^n) = n log A

If value of base is not mentioned then we assume it to be common logarithm so by default base become 10

So

Log 10 =1

Now

Log (10x / y^2)

= Log 10x - Log (y^2)

=Log 10 + Log x - 2 Log y

= 1 + m + n - 2 (m - n)

=1 + m + n - 2m + 2n

= 1 - m + 3n

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