Given that ᴱ⁰O₂/H₂O = +1.23V; ᴱ⁰S₂O₈²⁻/SO₄²⁻ = 2.05 V; ᴱ⁰Br₂/Br⁻ = +1.09 V; ᴱ⁰Au³⁺/Au = 1.4V. The strongest oxidizing agent is:
(A) O₂
(B) S₂O₈²⁻
(C) Au³⁺
(D) Br₂
Answers
Answered by
0
Answer:
according to my knowledge the answer is (C)
Answered by
1
Answer:
Right answer is B
Explanation:
strongest oxidising agent should be less reactive and have high Enot value
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