Given that, P+ 0 = R and that R is perpendicular to P. If [PL = IRI, then what is the angle between P and Q?
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Given P + Q = R with P = R and R is perpendicular to P . Consider a closed right angled triangle ABC with AC perpendicular to AB so that angle A is 90 degrees. Let P & Q be represented, respectively by the vectors AB and BC, where as vector AC represents R (make a rough sketch of the triangle ABC, it will help). Since P= R, therefore AB = AC implies ABC is an isosceles rt. angled triangle, which in turn gives angle ABC=angle BCA = (pi/4) . Therefore the angle between the vector AB & BC(or between P and Q)= (pi) - (pi/4) = (3pi/4) = 135 degrees.
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