given that p = 12 , Q=5 and R= 13 also P+Q=R then the angel between P and Q is
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Answered by
0
Answer:
Consider the problem
Let x is the angle between P and Q .
R
=
P
+
Q
∴13=
(5
2
+12
2
+(2×5×12×Cosx))
[∵∣
a
+
b
∣=
a
2
+b
2
+2abcosθ
]
⇒169=169+120cosx
⇒0=120cosx
⇒cosx=0
∴x=90
∘
=
2
π
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