Given that :–
\sf{ : \implies \: Initial \: Velocity \: (u) = 40}:⟹InitialVelocity(u)=40
\sf{ : \implies \: Final \: velocity \: (v) = 0}:⟹Finalvelocity(v)=0
\sf{: \implies \: Height \: (s) = ? }:⟹Height(s)=?
By applying the third equation of motion :–
\qquad \circ \: { \color{green}{ \underline{ \boxed{ \sf{ {v}^{2} - {u}^{2} = 2gs}}}}}∘
v
2
−u
2
=2gs
we get,
\qquad \leadsto \sf{0 - ( {40}^{2}) = - 2 \times 10 \times s}⇝0−(40
2
)=−2×10×s
\qquad \leadsto \sf{160= - 2 \times 10 \times s}⇝160=−2×10×s
\qquad \leadsto \sf{160= - \: 20 \times s}⇝160=−20×s
\qquad \leadsto \sf{s = \frac{160}{20} }⇝s=
20
160
\qquad \leadsto \sf{s ={ \cancel{ \frac{160}{20} }}}⇝s=
20
160
\qquad \leadsto \sf{s = \: 80 \: \: m/s}⇝s=80m/s
Toatl distance travelled by stone = upward distance + downwars distance
\sf \underbrace{ \mapsto\: 2 \: × \: s \: = \: 2 \: × \: 80 \: = \: 160}
↦2×s=2×80=160
\sf{Total \: Diaplacement =0}TotalDiaplacement =0
\sf{Since \: the \: initial \: and \: final \: point \: is \: same}Sincetheinitialandfinalpointissame
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Answer:
- The phenomena of the physical world collectively, including plants, animals, the landscape, and other features and products of the earth, as opposed to humans or human creations.
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