Question

Given that sin(A+B)=sinAcosB+CosASinB, find the value of Sin75°.​

Answer 1

HeYa...

Answer:

Putting A=45° and B=30° in Sin(A+B) = Sin A Cos B + Cos A Sin B,

Then,

sin(45°+30°) = sin45°cos30° + cos45°sin30°

sin75° = 1/√2 × √3/2 + 1/√2×1/2

sin75° = √3+1/2√2

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Answer 2

$\huge\bf{Answer:-}$

Refer the attachment.