GIVEN that sin(A+B)=sinAcosB+sinBcosA, then find the value of sin 75
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sin75° = sin(45°+30°)
=sin45°cos30° + sin30°cos45°
=(1/√2)×(√3/2) + (1/2)×(1/√2)
=√3/(2√2) + 1/(2√2)
=(√3+1)/(2√2)
=sin45°cos30° + sin30°cos45°
=(1/√2)×(√3/2) + (1/2)×(1/√2)
=√3/(2√2) + 1/(2√2)
=(√3+1)/(2√2)
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