Given that : sina , then CosA = ?
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Given that sinA =a/b then cosA is equal to
Sin^2 A = (a/b)^2.
cos^2A ,= 1 - (a/b)^2.
cosA = sqrt( b^2 - a^2)
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According to the question, sin θ =a/b We know, sin2 θ +cos2 θ =1 sin2 A = 1-cos2 A sin A = √(1-cos2 A So, cos θ = √(1-a2/b2 ) = √((b2-a2)/b2 ) = √(b2-a2 )/b Hence, cos θ = √(b2 – a2 )/bRead more on Sarthaks.com - https://www.sarthaks.com/883942/given-that-sin-a-b-then-cos-is-equal-to
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