A point charge of -2μC is placed at a distance of 5m from another point charge of 9μC in air. Calculate the value of electric potential at a point which is situated at a distance of 3m from both these charges?
Answers
Answer:
Consider at point P, the electric field is zero,
as Electric field,
E=
d
2
kq
at P,
x
2
kq
1
=
(50−x)
2
kq
2
⇒
x
2
4
=
(50−x)
2
9
⇒(
x
50−x
)
2
=
4
9
⇒
x
50−x
=±
2
3
⇒x=20cm OR x=−150cm (Not Applicable)
Hence, at a distance = 20 cm from A, E=0
Also, potential at that point,
V=
x
kq
1
+
50−x
kq
2
=9×10
9
×(
0.2
4×10
−6
+
0.3
9×10
−6
)=4.5×10
5
v
Hope it helps you!!!!!
Answer:
To calculate the electric potential at a point, we need to use the formula:
V = kq/r
where V is the electric potential, k is the Coulomb's constant (k = 9 x 10^9 N m^2/C^2), q is the charge, and r is the distance from the charge.
First, let's calculate the electric potential at the point due to the 9 micro coulomb charge:
V1 = kq1/r1
= (9 x 10^-6 C) * (1/(5 m))
= 1.8 x 10^6 V
where q1 = 9 micro coulomb and r1 = 5 m.
Next, let's calculate the electric potential at the same point due to the -2 micro coulomb charge:
V2 = kq2/r2
= (-2 x 10^-6 C) * (1/(5 m))
= -4 x 10^5 V
where q2 = -2 micro coulomb and r2 = 5 m.
Note that the negative sign in V2 indicates that the electric potential due to the negative charge is in the opposite direction.
Now, we need to add the two electric potentials to get the net electric potential at the point:
V = V1 + V2
= 1.8 x 10^6 V - 4 x 10^5 V
= 1.4 x 10^6 V
where V1 is the electric potential due to the 9 micro coulomb charge and V2 is the electric potential due to the -2 micro coulomb charge.
Finally, we need to calculate the electric potential at the point which is 3 m away from both charges. Using the same formula as before:
V = kq/r
= (9 x 10^-6 C + -2 x 10^-6 C) * (1/(3 m))
= 2.33 x 10^6 V
Therefore, the electric potential at a point which is 3 m away from both the charges is 2.33 x 10^6 V.