Given that tan teta = 1/√5 , what is the value of Cosec² theta - sec² theta / Cosec² theta + sec² theta.
Answers
Answered by
18
Tan ¢ = 1/√5
Therefore,
Cosec² ¢- Sec² ¢ / Cosec²¢ + Sec² ¢ = ( 1 + 5 ) - ( 1 + 1/5 ) / ( 1 + 5 ) + ( 1 + 1/5 )
=> ( 24/5 ) / ( 36/5 )
=> 24/36
=> 2/3.
Therefore,
Cosec² ¢- Sec² ¢ / Cosec²¢ + Sec² ¢ = ( 1 + 5 ) - ( 1 + 1/5 ) / ( 1 + 5 ) + ( 1 + 1/5 )
=> ( 24/5 ) / ( 36/5 )
=> 24/36
=> 2/3.
Answered by
11
Hey !
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Tan ¢ = 1 / √5
Cosec^2¢ + sec^2¢ / cosec^2¢ + sec^2¢
( 1 + 5 ) - ( 1 + 1/5 ) / 1 + 5 + ( 1 + 1/5 )
24/5 ÷ 36/5
Cancelling 5
24/36 = 2/3
___________________
✌
_____________________
Tan ¢ = 1 / √5
Cosec^2¢ + sec^2¢ / cosec^2¢ + sec^2¢
( 1 + 5 ) - ( 1 + 1/5 ) / 1 + 5 + ( 1 + 1/5 )
24/5 ÷ 36/5
Cancelling 5
24/36 = 2/3
___________________
✌
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