Given that tan theta=1/√3, the value of cosec square theta- sec square square theta/cosec square theta+ sec square theta =
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if tan∅=1/√3
Then, ∅=30°
Therefore,
Cosec²∅-sec²∅/cosec²∅ + sec²∅
Or,2²-(2/√3)²/2²+(2/√3)²
Or,4-4/3/4+4/3
Or,8/3/16/3
Or,24/48
Or,1/2
Answer- 1/2
Then, ∅=30°
Therefore,
Cosec²∅-sec²∅/cosec²∅ + sec²∅
Or,2²-(2/√3)²/2²+(2/√3)²
Or,4-4/3/4+4/3
Or,8/3/16/3
Or,24/48
Or,1/2
Answer- 1/2
Answered by
1
Answer:
1/2 will be the answer pls mark as brainlest
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