Question

Given that the boiling point of benzene is 80.1∘C at 1 atm and its boiling point elevation constant is 2.53∘Cm, what is the boiling point of a 0.370m solution of a nonvolatile solute in benzene?

Answer 1

Answer : The boiling point of solution is, $79.16^oC$

Solution :

Formula used for Elevation in boiling point :

$\Delta T_b=k_b\times m$

or,

$T_{solvent}-T_{solution}=k_b\times m$

where,

$T_{solvent}$ = boiling point  of benzene = $80.1^oC$

$T_{solution}$ = boiling point  of solution = ?

$k_b$ = elevation constant  = $2.53^oC\text{ m}$

m = molality  = 0.370 m

Now put all the given values in the above formula. we get the boiling point of solution.

$80.1^oC-T_{solution}=2.53^oC\text{ m}\times 0.370m$

$T_{solution}=79.16^oC$

Therefore, the boiling point of solution is, $79.16^oC$

Answer 2

Answer:

Answer : The boiling point of solution is, 79.16^oC79.16

o

C

Solution :

Formula used for Elevation in boiling point :

\Delta T_b=k_b\times mΔT

b

=k

b

×m

or,

T_{solvent}-T_{solution}=k_b\times mT

solvent

−T

solution

=k

b

×m

where,

T_{solvent}T

solvent

= boiling point of benzene = 80.1^oC80.1

o

C

T_{solution}T

solution

= boiling point of solution = ?

k_bk

b

= elevation constant = 2.53^oC\text{ m}2.53

o

C m

m = molality = 0.370 m

Now put all the given values in the above formula. we get the boiling point of solution.

80.1^oC-T_{solution}=2.53^oC\text{ m}\times 0.370m80.1

o

C−T

solution

=2.53

o

C m×0.370m

T_{solution}=79.16^oCT

solution

=79.16

o

C

Therefore, the boiling point of solution is, 79.16^oC79.16

o

C