Given that the equilibrium constant for the reaction
2SO2 + O2 ------> 2SO3
has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the reaction at the same temperature
SO3 -----> SO2+ ½O2
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Answer:278^(-0.5) = 0.05997
Explanation:The value of equilibrium constant is the initial value of equilibrium constant raised to the power of the number which is multiplied in the initial reaction to give the required reaction.Also its value is reciprocated if the direction is reversed
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