Given that the gradient of a straight line passes through points A (2,9 )and B (3q, 10) is – 4, find the value of q.
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Answer:
We know that the equation of line passing through point (x
0
,y
0
) whose slope is m is
(y−y
0
)=m(x−x
0
)
Thus the equation of line passing through the point (−4,3) whose slope is
2
1
is,
(y−3)=
2
1
(x+4)
⇒2(y−3)=(x+4)
⇒x−2y+10=0
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this is the method for this question
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