Question

Given that the slope of the tangent to a curve y = y(x) at any point (x, y) is 2y/x². If the curve passes through the centre of the circle x² + y² - 2x - 2y = 0, then its equation is:
(A)
x logₑ |y| = x - 1 (B) x logₑ |y| = -2(x - 1)
(C) x² logₑ |y| = -2(x - 1) (D) x logₑ |y| = 2(x - 1)

Answer 1

x logₑ |y| = x - 1 (B) x logₑ |y| = -2(x - 1)

(C) x² logₑ |y| = -2(x - 1) (D) x logₑ |y| = 2(x - 1)

Hope it's help

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