Given that two of the zeroes of the cubic poly-nomial ax3 + bx² + cx + d are 0, the third zero is
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Answer:
Let α,0,0 be the zeros of ax3+bx2+cx+d. Then, sum of zeros = -ba⇒α+0+0=-ba⇒α=-ba. Hence, the third zeros is -ba.
Step-by-step explanation:
Given two zeroes of a cubic polynomial=
ax3+bx 2+cx+d
are zero, Let third zero be y
then sum of zeroes = −b/a
⇒0+0+y= -b/a
⇒y= -b/a.
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