Question

given that two of the zeroes of the cubic polynomial ax3+bx2+cx+d are 0 then find the third zero

Answer 1

let the roots be p ,q ,r
two root let p and q be 0 (given)
we know that => sum of roots = -b/a
=> p + q + r = -b/a
=> 0 + 0 + r = -b/a
=> r = -(b/a)

Answer 2

Answer:

The third zero is -b/a

Step-by-step explanation:

Given,

Two of the zeroes of the cubic polynomial ax³ + bx² + cx + d are 0

Let zeroes of the equation be p, q, r

According to question,

Two zeroes [ p, q ] = 0, 0

We know,

Sum of roots = -b/a

Therefore,

By using relation between zeroes and coefficient of polynomial, we have:

p + q + r  = -b / a

Substituting the values of p and q,

0 + 0 + r = -b / a

r = -b/a

Third zero = r = -b/a

Hence,

The third zero is -b/a