Given that two of the zeroes of the cubic polynomial ax3+bx2+cx+d are 0 then find the third zero
Answers
Answered by
17
here is Ur answer dear.....
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Let the Roots be P,q, r two root
let P and q be 0 (given)
we know that = sum of roots = -b/a
=> P+q +r = -b/a
=> 0+0+r = -b/a
=> r = -(b/a). ans.
Hope this helps you.
☺
____________________________
Let the Roots be P,q, r two root
let P and q be 0 (given)
we know that = sum of roots = -b/a
=> P+q +r = -b/a
=> 0+0+r = -b/a
=> r = -(b/a). ans.
Hope this helps you.
☺
Answered by
6
Answer:
The third zero is -b/a
Step-by-step explanation:
Given,
Two of the zeroes of the cubic polynomial ax³ + bx² + cx + d are 0
Let zeroes of the equation be p, q, r
According to question,
Two zeroes [ p, q ] = 0, 0
We know,
Sum of roots = -b/a
Therefore,
By using relation between zeroes and coefficient of polynomial, we have:
p + q + r = -b / a
Substituting the values of p and q,
0 + 0 + r = -b / a
r = -b/a
Third zero = r = -b/a
Hence,
The third zero is -b/a
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