Question

Given that two of the zeroes of the cubic polynomial ax3+bx2+cx+d are 0 then find the third zero

Answer 1

ax+by+cy=0 ax.by.cy=0

Answer 2

let the zeroes be
$\alpha \: \beta \: \gamma$
let ,
$\alpha \: and \: \beta \: be \: 0$
now ,

sum of zeroes = -b/a

$\alpha + \beta + \gamma = - b \div a$
$0 + 0 + \gamma = - b \div a$


there the third zero = -b/a


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