given that two of the zeros of the polynomial are ax^3+bx^2+cx+d are 0 the what is the value of c ?
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Answer:
c = third zero
Given,
Two of the zeroes of the cubic polynomial ax³ + bx² + cx + d are 0
Let zeroes of the equation be p, q, r
According to question,
Two zeroes [ p, q ] = 0, 0
We know,
Sum of roots = -b/a
Therefore,
By using relation between zeroes and coefficient of polynomial, we have:
p + q + r = -b / a
Substituting the values of p and q,
0 + 0 + r = -b / a
r = -b/a
Third zero = r = -b/a
Hence,
The third zero is -b/a
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