Question

Given that (x-3) is a factor of 2x^3-ax^2-5x+6. find the value of a and factorise completely.​

Answer 1

Answer:

Since x-3 is a factor, therefore p(3)= 0

2(3)^3-a(3)^2-5(3)+6=0

2(27)-9a-15+6=0

54+6-15=9a

45=9a

45/9=a

5=a

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